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From Adaptive Population based Simplex
Revision as of 17:58, 16 July 2013 by 78.229.106.132 (Talk)
Math test
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$N=20*sqrt{D}$
$$ \operatorname{erfc}(x) = \frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt = \frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}} $$
\( N=\max\left(40+2\sqrt{D},\sqrt{40^{2}+\left(D+2\right)^{2}}\right)\tag{1} \)
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